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NEW QUESTION: 1
Welche der folgenden Aussagen zu den Testberichtsaktivitäten für ein Projekt, das ein iteratives Lebenszyklusmodell mit sehr kurzen Iterationen (z. B. zweiwöchige Iterationen) verwendet, ist richtig?
K2 1 Kredit
A. Testberichtsaktivitäten sind in einem iterativen Lebenszyklus immer noch wichtig. Die Berichte können verwendet werden, um Überprüfungssitzungen nach der Iteration durchzuführen, bevor mit der nächsten Iteration begonnen wird
B. Testberichtsaktivitäten können nicht durch die Verwendung eines iterativen Lebenszyklusmodells mit kurzen Iterationen beeinflusst werden
C. Testberichtsaktivitäten sind für Projekte, die ein iteratives Lebenszyklusmodell mit kurzen Iterationen verwenden, nicht wichtig
D. Testberichtsaktivitäten sind weniger wichtig für Projekte, die ein iteratives Lebenszyklusmodell mit kurzen Iterationen verwenden. Sie sollten am Ende der letzten Iteration ausgeführt werden
Answer: A

NEW QUESTION: 2
顧客はMicrosoft Windowsサーバー間で費用効果の高い方法でファイルを共有する必要があり、災害サポートを必要としています。 （2つ選択）リカバリー
A. データ重複排除の強化
B. Microsoft Azureサポート
C. ファイル分類インフラストラクチャ
D. デュアルコントローラーアーキテクチャ
E. DFSレプリケーション
Answer: A,B

NEW QUESTION: 3

A. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
D. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
Answer: A