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NEW QUESTION: 1
You are programming a buffer overflow exploit and you want to create a NOP sled of 200 bytes in the program exploit.c

What is the hexadecimal value of NOP instruction?
A. 0x60
B. 0x70
C. 0x90
D. 0x80
Answer: C

NEW QUESTION: 2
-- Exhibit -user@router> show configuration routing-options autonomous-system 65550;
user@router> show configuration protocols bgp
group ibgp { type internal; neighbor 10.0.3.5;
}
group ibgpv6 { type internal; local-address 2001:ffff::3:4; neighbor 2001:ffff::3:5;
}
group as65010 { family inet { unicast; } family inet6 { unicast; } export as65010-out; peer-as 65010; neighbor 172.16.0.6;
}
user@router> show configuration policy-options
policy-statement as65010-out { term locally-originated { from as-path local-only;
then {
metric 7000;
}
}
term from-as65222 {
from as-path as65222-orig;
then as-path-prepend "65550 65550 65550 65550";
}
term transit-as701 {
from as-path transit-as701;
then {
metric 6;
}
}
then accept;
}
as-path local-only "(.*)";
as-path as65222-orig ".* 65222";
as-path transit-as701 ".* 701 .*";
user@router> show route advertising-protocol bgp 172.16.0.6
inet.0: 43 destinations, 47 routes (43 active, 0 holddown, 0 hidden)
Prefix Nexthop MED Lclpref AS path
*10.0.2.0/30 Self 7000 I
*10.0.2.4/30 Self 7000 I
*10.0.2.8/30 Self 7000 I
*10.0.2.16/30 Self 7000 I
*10.0.3.3/32 Self 7000 I
* 10.0.3.4/32 Self 7000 I
* 10.0.3.5/32 Self 7000 I
* 10.0.4.8/30 Self 7000 I
* 10.0.8.8/30 Self 7000 I
* 10.0.9.9/32 Self 7000 I
* 10.255.255.1/32 Self 7000 I
* 64.142.88.0/24 Self 7000 I
* 130.130.0.0/16 Self 6 65222 46375 701 14203 I
* 131.131.131.0/24 Self 6 65222 46375 701 14203 I
* 132.132.0.0/25 Self 6 65222 46375 701 32934 I
* 133.133.0.0/25 Self 6 65222 46375 701 32934 I
* 134.134.0.0/25 Self 65222 46375 14203 I
* 135.135.0.0/25 Self 65222 46375 14203 14203 I
* 172.16.0.4/30 Self 7000 I
* 172.16.0.12/30 Self 7000 I
* 172.16.200.0/30 172.16.0.6 7000 I
* 192.0.2.0/24 172.16.0.6 7000 I
* 192.168.50.0/24 Self 7000 I
* 192.168.253.0/24 Self 7000 I
* 200.200.0.0/16 172.16.0.6 7000 I
* 200.200.0.1/32 172.16.0.6 7000 I
* 200.200.1.1/32 172.16.0.6 7000 I
* 200.200.200.200/32 172.16.0.6 7000 I
inet6.0: 23 destinations, 28 routes (23 active, 0 holddown, 0 hidden) Prefix Nexthop MED Lclpref AS path
* ::172.16.0.4/126 Self 7000 I
* 2001:1:1::/64 Self 7000 I
*2001:1:2::/64 Self 7000 I
*2001:ffff::3:3/128 Self 7000 I
*2001:ffff::3:4/128 Self 7000 I
*2001:ffff::3:5/128 Self 7000 I
*2001:ffff::9:7/128 Self 7000 I
user@router>
-- Exhibit -
Click the Exhibit button.
You are configuring an EBGP peer in a transit environment. You must advertise routes learned from other EBGP peers in your AS. Any routes originated from within your AS should have a MED of 7000 set. Any routes that originate in AS65222 should be prepended four times. Any routes that transit AS701 should have a MED set to 6. This scenario results in the unintended advertisement of internal 10.0.0.0/8 networks to your peer.
What caused the accidental advertisement of internal networks to your EBGP peer?
A. The BGP group as65010 is configured for both family inet unicast and family inet6 unicast protocol families.
B. Your AS number of 65550 is a private AS number.
C. The as-path local-only includes a misconfigured regular expression.
D. The export policy as65010-out is misconfigured.
Answer: D

NEW QUESTION: 3
How many Cisco UCS C220 servers are used in a Vblock System mini Advanced Management Pod (mini-AMP)?
A. 0
B. 1
C. 2
D. 3
Answer: A

NEW QUESTION: 4
MaxCompute SQL is suitable for processing less real-time massive data, and employs a syntax similar to that of SQL. The efficiency of data query can be improved through creating proper indexes in the table.
A. False
B. True
Answer: A