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NEW QUESTION: 1
What is the effect of specifying the "ENABLE PLUGGABLE DATABASE" clause in a "CREATE DATABASE" statement?
A. It will create a CDB with root and seed opened and one PDB mounted.
B. It will create a CDB with root opened and seed read only.
C. It will create a CDB that must be plugged into an existing CDB.
D. It will create a CDB with root opened and seed mounted.
E. It will create a multitenant container database (CDB) with only the root opened.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
* The CREATE DATABASE ... ENABLE PLUGGABLE DATABASE SQL statement creates a new CDB. If you do not specify the ENABLE PLUGGABLE DATABASE clause, then the newly created database is a non-CDB and can never contain PDBs.
Along with the root (CDB$ROOT), Oracle Database automatically creates a seed PDB (PDB$SEED). The following graphic shows a newly created CDB:

* Creating a PDB
Rather than constructing the data dictionary tables that define an empty PDB from scratch, and then populating its Obj$ and Dependency$ tables, the empty PDB is created when the CDB is created. (Here, we use empty to mean containing no customer-created artifacts.) It is referred to as the seed PDB and has the name PDB$Seed. Every CDB non-negotiably contains a seed PDB; it is non-negotiably always open in read-only mode. This has no conceptual significance; rather, it is just an optimization device. The create PDB operation is implemented as a special case of the clone PDB operation.

NEW QUESTION: 2
Your system has been upgraded from Oracle Database 10g to Oracle Database 11g. You imported SQL Tuning Sets (STS) from the previous version that contains important SQL statements. You are not sure about the elapsed time that the SQL statements will have in the new system due to the version change of the optimizer. Which tool provides a comparative report with respect to the elapsed time in both versions of the optimizer?
A. Automatic Workload Repository (AWR)compare period report
B. SQL Performance Analyzer (SPA)
C. SQL Tuning Advisor (STA)
D. SQL Access Advisor
Answer: B

NEW QUESTION: 3
架空の会社としての最初の日へようこそ。 LLCヘルプデスクの従業員。ヘルプデスクのチケットキューでチケットを処理してください。
チケットの詳細を表示するには、個々のティッカーをクリックしてください。添付ファイルを表示して問題を特定します。
[問題]ドロップダウンメニューから適切な問題を選択します。次に、[解像度]ドロップダウンメニューから最も効率的な解像度を選択します。最後に、適切なコマンドまたは検証を選択して、[解決の検証]ドロップダウンメニューから問題の修正を修正または確認します。


Answer:
Explanation:

NEW QUESTION: 4
A N8500 (V200R001) clustered NAS system with a set of storage units at the back end. Three RAID Groups,
respectively named RG1, RG2, RG3 have been created on the storage unit. There are two LUNs under each
RAID group, the capacity of each LUN is 12G.
The names are RG1-LUN1, RG1-LUN2, RG2-LUN1, RG2-LUN2, RG3-LUN1, RG3-LUN2, and all LUNs
are added to one in storage pool. The purpose is to create a file system based on these LUNs. What of the
following will certainly create a failure?
A. fs create mirrored fs02 10g 2 RG1-LUN2, RG2-LUN2 stripeunit = 2048 blksize = 8192
B. fs create striped-miiro fs04 20g 2 3 RG1-LUn1, RG1-LUN2, RG2-LUN1, RG2-LUN2, RG3-LUN1,
RG3-LUN2 protection = disk stripeunit = 512 blksize = 1024
C. fs create mirrored-stripe fs03 10g 2 2 RG1-LUn1, RG2-LUN1 protection = disk stripeunit = 2048
blksize = 8192
D. fs create striped fs01 10g 3 RG1-LUN1, RG2-LUN1, RG3-LUN1 stripeunit = 2048 blksize = 8192
Answer: C