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NEW QUESTION: 1
Refer to the exhibit.

Based on the agent idle time and call flow in the exhibit, to which location will the call be queued?
A. Skill 77
B. Location 2
C. Location 4
D. Location 1
Answer: D

NEW QUESTION: 2
Lab - CLI Configuration



Attention:
In practical examinations, please note the following, the actual information will prevail.
1. Name of the router is xxx
2. Enable. secret password is xxx
3. Password In access user EXEC mode using the console is xxx
4. The password to allow telnet access to the router is xxx
5. IP information
Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Gotha
Gotha(config)#enable secret mi222ke
Gotha(config)#line console 0
Gotha(config-line)#password G8tors1
Gotha(config-line)#exit
Gotha(config)#line vty 0 4
Gotha(config-line)#password dun63lap
Gotha(config-line)#login
Gotha(config-line)#exit
Gotha(config)#interface fa0/0
Gotha(config-if)#no shutdown
Gotha(config-if)#ip address 209.165.201.4 255.255.255.224
Gotha(config)#interface s0/0/0
Gotha(config-if)#ip address 192.0.2.190 255.255.255.240
Gotha(config-if)#no shutdown
Gotha(config-if)#exit
Gotha(config)#router rip
Gotha(config-router)#version 2
Gotha(config-router)#network 209.165.201.0
Gotha(config-router)#network 192.0.2.176
Gotha(config-router)#end
Gotha#copy run start

NEW QUESTION: 3
Identify two true statements about an Oracle WebLogic Server JMS Connection Factory.
A. A JMS Connection Factory's Default Priority and Default Time-to-Live attribute cannot be modified after the Connection Factory is created.
B. A default JMS Connection Factory exists and is named weblogic.jms.connections
C. A Connection Factory can be targeted to only one WebLogic Server.
D. A JMS Connection factory can be created as a system module resource within the administration console.
Answer: A,D
Explanation:
Reference: Programming WebLogic JMS, Understanding WebLogic JMS

NEW QUESTION: 4
View the Exhibit and examine the structure of the CUSTOMERS table .Which statement would display the highest credit limit available in each income level in each city in the CUSTOMERS table?

A. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_city, cust_income_level, MAX(cust_credit_limit);
B. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_city, cust_income_level;
C. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_credit_limit, cust_income_level, cust_city ;
D. SELECT cust_city, cust_income_level, MAX(cust_credit_limit ) FROM customers GROUP BY cust_city, cust_income_level, cust_credit_limit;
Answer: B