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NEW QUESTION: 1
Welches Ereignis ist aufgetreten, wenn eine Nachricht auf Benachrichtigungsebene an einen Syslog-Server gesendet wird?
A. Ein Netzwerkgerät wurde neu gestartet
B. Eine Routing-Instanz ist geflattert
C. Ein Debug-Vorgang wird ausgeführt
D. Eine ARP-Inspektion ist fehlgeschlagen
Answer: A

NEW QUESTION: 2
ユーザーが、CloudWatch詳細モニタリングが無効になっているAuto Scalingの起動設定を作成しました。
ユーザーは、詳細な監視を有効にしたいと考えています。
ユーザーはどのようにこれを達成できますか？
A. CLIで起動構成を更新して、InstanceMonitoringDisabled = falseを設定します
B. 詳細監視を有効にして新しい起動構成を作成し、Auto Scalingグループを更新します
C. ユーザーは、AWSコンソールからAuto Scalingグループを変更して、詳細な監視を有効にする必要があります
D. CLIで起動構成を更新して、InstanceMonitoring.Enabled = trueを設定します
Answer: B
Explanation:
Explanation
CloudWatch is used to monitor AWS as well as the custom services. To enable detailed instance monitoring for a new Auto Scaling group, the user does not need to take any extra steps. When the user creates the Auto Scaling launch config as the first step for creating an Auto Scaling group, each launch configuration contains a flag named InstanceMonitoring.Enabled. The default value of this flag is true. When the user has created a launch configuration with InstanceMonitoring.Enabled = false it will involve multiple steps to enable detail monitoring. The steps are:
http://docs.aws.amazon.com/AmazonCloudWatch/latest/DeveloperGuide/as-metricscollected.html

NEW QUESTION: 3
Given the code fragment:

What is the result?
A. Compilation fails
B. 5 : 5
C. 5 : 10
D. 10 : 10
Answer: D

NEW QUESTION: 4
DRAG DROP




Answer:
Explanation:

Explanation:

Box 1: SELECT..COALESCE...
The COALESCE function evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: ..LEFT OUTER JOIN..
The LEFT JOIN (LEFT OUTER JOIN) keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. A customer might have no orders so the right table must be allowed have a NULL value.
Box 3: ON c.custid = o.custid
We JOIN on the custID column, which is available in both tables.
Box 4: GROUP BY c.custid
References:
https://technet.microsoft.com/en-us/library/ms189499(v=sql.110).aspx
http://www.w3schools.com/sql/sql_join_left.asp