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NEW QUESTION: 1
保留ステータスの請求書の請求日が2018年1月20日の場合、会社が2018年2月に買掛金未計上トランザクションスイーププログラムを実行するとどうなりますか？
A. 未計上のすべての請求書の会計日は、次の期間の最終日である2018年2月28日に変更されます。
B. すべての未計上の請求書の会計日は、次の期間の同じ日に、2018年2月20日に変更されます。
C. すべての未計上の請求書の会計日は、次の期間の初日である2018年2月1日に変更されます。
D. すべての未計上の請求書の会計日は2018年1月20日のまま変更されません。
Answer: C
Explanation:
Explanation
Run the Payables Unaccounted Transactions Sweep program to transfer unaccounted transactions from one accounting period to another. If your accounting practices permit it, use this program to change the accounting date of the transactions to the next open period.
The program transfers unaccounted transactions to the period you specify by updating the accounting dates to the first day of the new period.
References:https://docs.oracle.com/cloud/farel8/financialscs_gs/FAPPP/F1011880AN1B948.htm

NEW QUESTION: 2
You are configuring a table to use the Always Encrypted feature. The table will have the columns configured as shown in the following table.

All the columns will be encrypted by using the AEAD_AES_256_CBC_HMAC_SHA_256algorithm. Values will be stored in the most secure way possible.
Which two columns should use randomized encryption? Each correct answer presents a complete solution.
NOTE: Each correct selection is worth one point.
A. Tax Id
B. Address
C. LastName
D. Gender
Answer: B,D
Explanation:
Explanation/Reference:
Explanation:
Always Encrypted supports two types of encryption: randomized encryption and deterministic encryption.
Randomized encryption uses a method that encrypts data in a less predictable manner. Randomized encryption is more secure, but prevents searching, grouping, indexing, and joining on encrypted columns.
References: https://docs.microsoft.com/en-us/sql/relational-databases/security/encryption/always- encrypted-database-engine?view=sql-server-2017

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:

The tables include the following records:
Customer_CRMSystem

Customer_HRSystem

Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to display customers who appear in both tables and have a proper CustomerCode.
Which Transact-SQL statement should you run?
A:

B:

C:

D:

E:

A. Option D
B. Option A
C. Option B
D. Option C
E. Option E
Answer: B
Explanation:
Explanation/Reference:
Explanation:
When there are null values in the columns of the tables being joined, the null values do not match each other. The presence of null values in a column from one of the tables being joined can be returned only by using an outer join (unless the WHERE clause excludes null values).
References: https://technet.microsoft.com/en-us/library/ms190409(v=sql.105).aspx