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NEW QUESTION: 1
Welche Customizing-Aktivitäten führen Sie im Gemeinkosten-Controlling durch?
A. Kostenstellenkategorien definieren
B. Kalkulationsvariantenparameter pflegen
C. Kostenstellentypen definieren
D. Wertfelder erstellen
Answer: C

NEW QUESTION: 2
Which three components comprise the Citrix License Server? (Choose three.)
A. SOAP service
B. Startup license
C. Microsoft Internet Information Services (IIS) Server
D. vendor Daemon
E. Apache Web Server
F. Options file
Answer: B,D,F
Explanation:
Explanation/Reference:
Reference https://myxenapp.com/2013/04/19/citrix-license/

NEW QUESTION: 3
管理者が着信の復号化に問題が発生しました。 管理者は、トリアージの一部としてどのオプションを調査する必要がありますか？
A. SSLをターゲットサーバに許可するセキュリティポリシールール
B. HSMからの証明書のインポート
C. CRLへのファイアウォール接続
D. "信頼"を有効にしてファイアウォールにインポートされたルート証明書
Answer: B

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: G
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx