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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The domain contains two member servers named Server1 and Server2. All servers run Windows Server
2012 R2.
Server1 and Server2 have the Failover Clustering feature installed. The servers are configured as nodes in a failover cluster named Cluster1. Cluster1 contains a cluster disk resource.
A developer creates an application named App1. App1 is NOT a cluster-aware application.
App1 runs as a service. App1 stores date on the cluster disk resource.
You need to ensure that App1 runs in Cluster1. The solution must minimize development effort.
Which cmdlet should you run?
A. Add-ClusterGenericApplicationRole
B. Add-ClusterGenericServiceRole
C. Add-ClusterServerRole
D. Add-ClusterScaleOutFileServerRole
Answer: A
Explanation:
Add-ClusterGenericApplicationRole
Configure high availability for an application that was not originally designed to run in a failover cluster.
If you run an application as a Generic Application, the cluster software will start the application, then periodically query the operating system to see whether the application appears to be running. If so, it is presumed to be online, and will not be restarted or failed over.
EXAMPLE 1.
Command Prompt: C:\PS>
Add-ClusterGenericApplicationRole -CommandLine NewApplication.exe
Name OwnerNode State
---- --------- -----
cluster1GenApp node2 Online
Description
-----------
This command configures NewApplication.exe as a generic clustered application. A default name will be used for client access and this application requires no storage.
Reference: Add-ClusterGenericApplicationRole
http://technet.microsoft.com/en-us/library/ee460976.aspx

NEW QUESTION: 2
A two-year old has been in the hospital for 3 weeks and seldom seen family members due to isolation precautions. Which of the following hospitalization changes is most like to be occurring?
A. Guilt
B. Separation anxiety
C. Shame
D. Trust
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Separation anxiety can easily occur after six months during hospitalization.

NEW QUESTION: 3
If you know expected value is 500 and the standard deviation is 12, you can say with approximately a 95 percent confidence rating which of the following?
A. The activity will take from 494 to 506 days.
B. The activity will take from 464 to 536 days.
C. The activity will take from 476 to 524 days.
D. The activity will take from 488 to 512 days.
Answer: C
Explanation:
There is a 95 percent probability that the work will finish within plus or minus two standard deviations. The expected value is 500, and the standard deviation times 2 is 24, so the activity will take from 476 to 524 days.